Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - P.S. Problem Solving - Page 505: 8a

Answer

If $f(x)$ is an even function then $h(x)=[f(x)]^2$ is also an even function.

Work Step by Step

If $f(x)$ is an even function, then $f(-x)=f(x)$. $h(-x)=[f(-x)]^2=[f(x)]^2=h(x)$ If $h(-x)=h(x)$, we can conclude that $h(x)$ is an even function.
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