Answer
$h(x)=cos^2x$ is even.
Work Step by Step
Notice the symmetry of $cos^2x$ with respect to the y-axis.
Also, $cos(-x)=cos~x$. Then:
$h(-x)=cos^2(-x)=(cos~x)^2=cos^2x=h(x)$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 6 - P.S. Problem Solving - Page 505: 7a
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