Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - P.S. Problem Solving - Page 505: 7a

Answer

$h(x)=cos^2x$ is even.
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Work Step by Step

Notice the symmetry of $cos^2x$ with respect to the y-axis. Also, $cos(-x)=cos~x$. Then: $h(-x)=cos^2(-x)=(cos~x)^2=cos^2x=h(x)$
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