Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - P.S. Problem Solving - Page 505: 4a


True. In fact, $f(t+nc)=f(t)$, where $n$ is an integer.

Work Step by Step

$f(t-2c)=f[(t-2c)+c]=f(t-c)$ $f(t-c)=f[(t-c)+c]=f(t)$. So: $f(t-2c)=f(t)$
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