## Algebra and Trigonometry 10th Edition

$x=6$ and $y=0$
$\dfrac{5x+20}{x^2-2x-24}=\dfrac{5(x+4)}{(x+4)(x-6)}$ or, $x-6=0 \implies x=6$ Find the horizontal asymptotes. The degree of the numerator is equal to the degree of the denominator. $y=0$ So, $x=6$ and $y=0$