Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 4 - Review Exercises - Page 352: 9


$x=6$ and $y=0$

Work Step by Step

$\dfrac{5x+20}{x^2-2x-24}=\dfrac{5(x+4)}{(x+4)(x-6)}$ or, $x-6=0 \implies x=6$ Find the horizontal asymptotes. The degree of the numerator is equal to the degree of the denominator. $y=0$ So, $x=6$ and $y=0$
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