## Algebra and Trigonometry 10th Edition

$x \gt 4$
We have: $30=(y-2(2))(x-2(2))$ $\implies 30=(y-4)(x-4)$ So, $y=\dfrac{30}{x-4}+4$ Now, $y=\dfrac{4x+14}{x-4}$ or, $xy=4x+4y+14$ or, $xy=4x+4(\dfrac{4x+14}{x-4}) +14$ Thus, $A=xy=\dfrac{2x(2x+7)}{x-4}$ We find that the margins are 2 inches wide, so $x$ must be greater than $4$.