Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 4 - Review Exercises - Page 352: 12b


$176;528; 1584$

Work Step by Step

We will substitute $p=25, 50, 75$ in the expression. So, we have: $C=\dfrac{528(25)}{100-25}=176$ $C=\dfrac{528(50)}{100-50}=528$ $C=\dfrac{528(75)}{100-75}=1584$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.