Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 4 - Review Exercises - Page 352: 12b

Answer

$176;528; 1584$

Work Step by Step

We will substitute $p=25, 50, 75$ in the expression. So, we have: $C=\dfrac{528(25)}{100-25}=176$ $C=\dfrac{528(50)}{100-50}=528$ $C=\dfrac{528(75)}{100-75}=1584$
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