Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 4 - Review Exercises - Page 352: 31b


$100.9; 10.9 ; 1.9$

Work Step by Step

We will substitute $p=1000, 10000, 100000$ in the expression. So, we have: $C=\dfrac{100000+0.9(1000)}{1000}=100.9$ $C=\dfrac{100000+0.9(10000)}{10000}=10.9$ $C=\dfrac{100000+0.9(100000)}{100000}=1.9$
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