# Chapter 4 - 4.4 - Translations of Conics - 4.4 Exercises - Page 347: 29

Vertex: $(h, k)=(5,\dfrac{-1}{2})$ Directrix: $x=\dfrac{9}{2}$ Focus: $(\dfrac{11}{2},\dfrac{-1}{2})$

#### Work Step by Step

We need to write the standard form of a parabola with a horizontal axis as follows: $(y+\dfrac{1}{2})^2=4(\dfrac{1}{2})(x-5)$ Now, Vertex: $(h, k)=(5,\dfrac{-1}{2})$ Directrix: $x=h-p=\dfrac{9}{2}$ Focus: $(h+p,k)=(\dfrac{11}{2},\dfrac{-1}{2})$

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