#### Answer

Hyperbola shifted 2 units left and 3 units up

#### Work Step by Step

$\frac{(x+2)^2}{4}-\frac{(y-3)^2}{9}=1$
The first aspect to notice is both the x term and y term are squared. The second aspect to notice is the y term is negative and the x term is positive and both are divided by unequal numbers (4 and 9). This means the conic is a hyperbola. The $(x+2)$ means that the center is shifted two units left (along the x-axis). The $(y-3)$ means that the center is shifted three units up (the y-axis).