Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 4 - 4.4 - Translations of Conics - 4.4 Exercises - Page 347: 22


$(x-5)^2+y^2=9$ Center: $(5,0)$ Radius: $r=3$

Work Step by Step

$x^2+y^2-10x+16=0$ Notice that $-10x=-2(5)x$ and that $5^2=25$ $x^2-10x+25-25+y^2+16=0$ $(x^2-10x+25)+y^2=25-16$ $(x-5)^2+y^2=9$ The equation of a circle in standard form: $(x-h)^2+(y-k)^2=r^2$ in which $(h,k)$ is the center and $r$ is the radius $(x-5)^2+(y-0)^2=3^2$ Center: $(5,0)$ Radius: $r=3$
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