Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 4 - 4.4 - Translations of Conics - 4.4 Exercises - Page 347: 19

Answer

Center: $(1,0)$ Radius: $r=\sqrt {10}$

Work Step by Step

The equation of a circle in standard form: $(x-h)^2+(y-k)^2=r^2$ in which $(h,k)$ is the center and $r$ is the radius $(x-1)^2+y^2=10$ $(x-1)^2+(y-0)^2=(\sqrt 10)^2$ Center: $(1,0)$ Radius: $r=\sqrt {10}$
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