Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 3 - Review Exercises - Page 300: 20



Work Step by Step

Vertex: $(h,k)=(-\frac{1}{4},7)$ Standard form: $y=a(x-h)^2+k$ $y=a[x-(-\frac{1}{4})]^2+7$ $y=a(x+\frac{1}{4})^2+7$ Now, use the point $(\frac{3}{4},\frac{49}{8})$ to find $a$: $\frac{49}{8}=a(\frac{3}{4}+\frac{1}{4})^2+7$ $\frac{49}{8}-7=a(1)^2$ $a=-\frac{7}{8}$ $y=-\frac{7}{8}(x+\frac{1}{4})^2+7$
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