Answer
$y=-(x-6)^2$
Work Step by Step
Vertex: $(h,k)=(6,0)$
Standard form:
$y=a(x-h)^2+k$
$y=a(x-6)^2+0$
$y=a(x-6)^2$
Now, use the point $(3,-9)$ to find $a$:
$-9=a(3-6)^2+2$
$-9=a(9)$
$a=\frac{-9}{9}=-1$
$y=-(x-6)^2$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 3 - Review Exercises - Page 300: 17
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