Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 3 - Review Exercises - Page 300: 16

Answer

$y=\frac{1}{4}(x-2)^2+2$

Work Step by Step

Vertex: $(h,k)=(2,2)$ Standard form: $y=a(x-h)^2+k$ $y=a(x-2)^2+2$ Now, use the point $(0,3)$ to find $a$: $3=a(0-2)^2+2$ $3-2=a(4)$ $a=\frac{1}{4}$ $y=\frac{1}{4}(x-2)^2+2$
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