## Algebra and Trigonometry 10th Edition

Domain: all the real numbers such that $x\leq3$ The zero: $x=-97$
$f(x)=10-\sqrt {3-x}$ Domain: $3-x\geq0$ $-x\geq-3$ $x\leq3$ The zeros: $f(x)=0$ $10-\sqrt {3-x}=0$ $10=\sqrt {3-x}~~$ (Square both sides) $100=3-x$ $x=3-100$ $x=-97$ Check the zero: $10-\sqrt {3-x}=10-\sqrt {3-(-97)}=10-10=0$