Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 2 - Chapter Test - Page 235: 2

Answer

$y=\frac{5}{3}x-\frac{1}{3}$
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Work Step by Step

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{\frac{4}{3}-(-7)}{1-(-4)}=\frac{\frac{25}{3}}{5}=\frac{5}{3}$ $(y-y_1)=m(x-x_1)$ $y-(-7)=\frac{5}{3}[x-(-4)]$ $y+7=\frac{5}{3}x+\frac{20}{3}$ $y=\frac{5}{3}x+\frac{20}{3}-7$ $y=\frac{5}{3}x-\frac{1}{3}$
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