Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 2 - 2.7 - Inverse Functions - 2.7 Exercises - Page 229: 87

Answer

$(f~o~g)^{-1}=\frac{1}{2}x+\frac{1}{2}$

Work Step by Step

$f~o~g=f(g(x))=f(2x-5)=2x-5+4=2x-1~~$ (Replace $f~o~g$ by $y$) $y=2x-1~~$ (Interchange $x$ and $y$): $x=2y-1$ $x+1=2y$ $y=\frac{1}{2}x+\frac{1}{2}$ $(f~o~g)^{-1}=\frac{1}{2}x+\frac{1}{2}$
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