## Algebra and Trigonometry 10th Edition

$(f^{-1}~o~g^{-1})(-1)=32$
$f(x)=\frac{1}{8}x-3$ $y=\frac{1}{8}x-3~~$ (Interchange $x$ and $y$): $x=\frac{1}{8}y-3$ $x+3=\frac{1}{8}y$ $y=8x+24$ $f^{-1}(x)=8x+24$ $g(x)=x^3$ $y=x^3~~$ (Interchange $x$ and $y$): $x=y^3$ $y=\sqrt[3] x$ $g^{-1}(x)=\sqrt[3] x$ $(f^{-1}~o~g^{-1})(-1)=f^{-1}(g^{-1}(1))=f^{-1}(\sqrt[3] 1)=f^{-1}(1)=8(1)+24=32$