## Algebra and Trigonometry 10th Edition

$f^{-1} (x)=\sqrt x-6$ Domain of the function $f$ is: $[-6, \infty)$. Domain of the inverse of function $f$ is: $[0, \infty)$.
We have $y=(x+6)^2$ To compute the inverse, we will have to interchange $x$ and $y$. $x=(y+6)^2$ Re-write as: $y=\sqrt x-6$ Replace $y$ with $f^{-1} (x)$. so, $f^{-1} (x)=\sqrt x-6$