Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11824 - 11.6 - Counting Principles - 11.6 Exercises - Page 824: 45

Answer

2520 distinguishable permutations.

Work Step by Step

2 A's and one of the other 5 letters. Total: 7 letters. $\frac{7!}{2!~1!~1!~1!~1!~1!}=\frac{5040}{2}=2520$
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