Answer
$_9C_9=1$
Work Step by Step
$_nC_r=\frac{n!}{(n-r)!~n!}$
$_9C_9=\frac{9!}{(9-9)!~9!}=\frac{9!}{0!~9!}=1$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11824 - 11.6 - Counting Principles - 11.6 Exercises - Page 824: 51
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