## Algebra and Trigonometry 10th Edition

Published by Cengage Learning

# Chapter 11824 - 11.6 - Counting Principles - 11.6 Exercises - Page 824: 41

#### Answer

There are $1,816,214,400$ different batting orders.

#### Work Step by Step

The order in which the players are selected is important. It is a permutation of 9 players from a group of 15 players. $_{15}P_9=\frac{15!}{(15-9)!}=\frac{15\times14\times13\times12\times11\times10\times9\times8\times7\times6!}{6!}=1,816,214,400$

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