Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11824 - 11.6 - Counting Principles - 11.6 Exercises - Page 824: 26

Answer

There are $117,600$ different lock combinations.

Work Step by Step

It is necessary to select 3 numbers from 50 in the correct order. So, the order is important. It is a permutation of 3 numbers from a group of 50 numbers. $_{50}P_3=\frac{50!}{(50-3)!}=\frac{50\times49\times48\times47!}{47!}=117,600$
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