## Algebra and Trigonometry 10th Edition

We can check whether they solve the inequality by plugging in the different values and seeing if they satisfy the inequality: a) $\frac{3(-2)^2}{(-2)^2+4}=\frac{12}{8}\gt1$, thus no b) $\frac{3(-1)^2}{(-1)^2+4}=\frac{3}{5}\lt1$, thus yes c) $\frac{3(0)^2}{(0)^2+4}=\frac{0}{4}\lt1$, thus yes d) $\frac{3(3)^2}{(3)^2+4}=\frac{27}{13}\gt1$, thus no