## Algebra and Trigonometry 10th Edition

$\frac{x}{x+2}-\frac{2}{x-1}=0$ (Make the expression = 0) $\frac{x(x-1)-2(x+2)}{(x-1)(x+2)}=0$ $\frac{x^2-3x-4}{(x-1)(x+2)}=0$ $\frac{x^2+x-4x-4}{(x-1)(x+2)}=\frac{x(x+1)-4(x+1)}{(x-1)(x+2)}=0$ $\frac{(x+1)(x-4)}{(x-1)(x+2)}=0$ Find the values of x that either satisfy the expression or make the expression undefined. Hence x = -1, 4, 1, -2