## Algebra and Trigonometry 10th Edition

$x^2+3x+8\gt0\\(x+1.5)^2-2.25+8\gt0\\(x+1.5)^2+6.75\gt0\\(x+1.5)^2\gt-6.75$ but we know that $a^2\geq0$ for all $a$ so all numbers satisfy this inequality. Thus the solution set is the whole set of real numbers.