## Algebra and Trigonometry 10th Edition

All real numbers solve the inequality apart from $x=5$.
$x^2-8x+16=(x-5)^2\gt0$ but we know that $a^2\geq0$ for all $a$, so the only case which is not a solution is when $x-5=0\\x=5$. Thus all real numbers solve the inequality apart from $x=5$.