Answer
$-2
Work Step by Step
Apply absolute rule:
If $|u|\lt a,~a\gt 0$, then $-a\lt u\lt a$.
Take $u=1-2x$ and $a=5$.
$$-5\lt1-2x\lt5$$
$$1-2x\gt-5\text{ and }1-2x\lt5$$
$$1-2x-1\gt-5-1\text{ and }1-2x-1\lt5-1$$
$$-2x\gt-6\text{ and }-2x\lt4$$
$$\frac{-2x}{-2}\lt\frac{-6}{-2}\text{ and }\frac{-2x}{-2}\gt\frac{4}{-2}$$
$$x\lt3\text{ and }x\gt-2$$
Rearranging:
$$-2
