Answer
$-6\lt x\leq1$
See graph
Work Step by Step
For
$$-9\leq-2x-7$$
$$-9+7\leq-2x-7+7$$
$$-2\leq-2x$$
$$\frac{-2}{-2}\geq\frac{-2x}{-2}$$
$$1\geq x$$
$$x\leq1$$
For
$$-2x-7\lt5$$
$$-2x-7+7\lt5+7$$
$$-2x\lt12$$
$$\frac{-2x}{-2}\gt\frac{12}{-2}$$
$$x\gt-6$$
For
$$x\leq1\text{ and }x\gt-6$$
$$-6\lt x\leq1$$
The graph is as shown.