Answer
$-6\lt x\lt 6$
See graph
Work Step by Step
Using the absolute rule:
If $|u|\lt a,~a\gt 0$, then $-a\lt u\lt a$.
With $u=\frac{x}{3}$ and $a=2$:
$$\frac{x}{3}\lt2\text{ and }\frac{x}{3}\gt2$$
$$x\lt-6\text{ and }x\gt6$$
Combining:
$$-6\lt x\lt 6$$
The graph of the solution set is as shown.
