Chapter 1 - 1.7 - Linear Inequalities in One Variable - 1.7 Exercises - Page 137: 45

$x\lt-2\text{ or }x\gt2$ See graph

Using the absolute rule: If $|u|\gt a,~a\gt 0$, then $u\lt-a\text{ or }u\gt a$. With $u=\frac{x}{2}$ and $a=1$: $$\frac{x}{2}\lt-1\text{ or }\frac{x}{2}\gt1$$ $$x\lt-2\text{ or }x\gt2$$ The graph of the solution set is as shown.