Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.5 - Complex Numbers - 1.5 Exercises - Page 120: 84



Work Step by Step

Use: $i^2=-1$ $\frac{1}{(2i)^3}=\frac{1}{8i^3}=\frac{1}{8i^3}\frac{i}{i}=\frac{i}{8i^4}=\frac{i}{8(i^2)^2}=\frac{i}{8(-1)^2}=\frac{i}{8}=\frac{1}{8}i$
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