## Algebra and Trigonometry 10th Edition

x = $-2+\frac{i}{2}$ or $-2-\frac{i}{2}$
$4x^2+16x+17=0$ $4x^2+16x+16=-1$ $(2x+4)^2=-1$ $(2x+4)=+i$ or $-i$ $2x= -4+i$ or $-4-i$ $x = -2+i/2$ or $-2-i/2$