Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.5 - Complex Numbers - 1.5 Exercises - Page 120: 68


Solutions: $x=-3+i$ $x=-3-i$

Work Step by Step

$x^2+6x+10=0~~$ ($a=1,b=6,c=10$): $x=\frac{-b±\sqrt {b^2-4ac}}{2a}=\frac{-6±\sqrt {6^2-4(1)(10)}}{2(1)}=\frac{-6±\sqrt {-4}}{2}=\frac{-6±2i}{2}=-3±i$ $x=-3+i$ or $x=-3-i$
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