#### Answer

The solution is 1

#### Work Step by Step

$\frac{4}{x-3}$-$\frac{1}{x}$=$\frac{6}{x(x-3)}$
x(x-3)[$\frac{4}{x-3}$-$\frac{1}{x}$]=x(x-3)$\frac{6}{x(x-3)}$
x(x-3)$\frac{4}{x-3}$-x(x-3)$\frac{1}{x}$=x(x-3)$\frac{6}{x(x-3)}$
4x-(x-3)=6
4x-x+3=6
3x+3=6
3x=6-3
3x=3
x=1
The solution is 1
Check
Let x=1
$\frac{4}{x-3}$-$\frac{1}{x}$=$\frac{6}{x(x-3)}$
$\frac{4}{1-3}$-$\frac{1}{1}$=$\frac{6}{1(1-3)}$
$\frac{4}{-2}$-1=$\frac{6}{-2}$
-2-1=-3
-3=-3