Answer
no solution
Work Step by Step
$\frac{2}{x+1}$-$\frac{1}{x}$=1
x(x+1)[$\frac{2}{x+1}$-$\frac{1}{x}$]=1x(x+1)
x(x+1)$\frac{2}{x+1}$-x(x+1)$\frac{1}{x}$=1x(x+1)
2x-(x+1)=$x^{2}$+x
2x-x-1=$x^{2}$+x
x-1=$x^{2}$+x
0= $x^{2}$+x-x+1
0=$x^{2}$+1
-1=$x^{2}$ no solution