#### Answer

The solution is 3

#### Work Step by Step

$\frac{1}{x}$+$\frac{2}{3}$=$\frac{3}{x}$
3x($\frac{1}{x}$+$\frac{2}{3}$)=3x$\frac{3}{x}$
3x$\frac{1}{x}$+3x$\frac{2}{3}$=3x$\frac{3}{x}$
3+2x=9
2x=6
x=3
The solution is 3
Check
Let x=3
$\frac{1}{x}$+$\frac{2}{3}$=$\frac{3}{x}$
$\frac{1}{3}$+$\frac{2}{3}$=$\frac{3}{3}$
$\frac{3}{3}$=$\frac{3}{3}$