Answer
$\frac{x-1}{(x+1)x}$
Work Step by Step
$\frac{2}{x+1}$-$\frac{1}{x}$=
$\frac{2*x}{(x+1)*x}$-$\frac{1(x+1)}{x(x+1)}$=
$\frac{2x-(x+1)}{(x+1)x}$=$\frac{2x-x-1}{(x+1)x}$=
$\frac{x-1}{(x+1)x}$
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