#### Answer

$\frac{x-1}{(x+1)x}$

#### Work Step by Step

$\frac{2}{x+1}$-$\frac{1}{x}$=
$\frac{2*x}{(x+1)*x}$-$\frac{1(x+1)}{x(x+1)}$=
$\frac{2x-(x+1)}{(x+1)x}$=$\frac{2x-x-1}{(x+1)x}$=
$\frac{x-1}{(x+1)x}$

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$\frac{x-1}{(x+1)x}$

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