Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.5 - Integrated Review - Summary on Rational Expressions - Page 526: 5

Answer

$\frac{x-1}{(x+1)x}$

Work Step by Step

$\frac{2}{x+1}$-$\frac{1}{x}$= $\frac{2*x}{(x+1)*x}$-$\frac{1(x+1)}{x(x+1)}$= $\frac{2x-(x+1)}{(x+1)x}$=$\frac{2x-x-1}{(x+1)x}$= $\frac{x-1}{(x+1)x}$
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