Answer
$\frac{z}{3(9z-5)}$
Work Step by Step
$\frac{9z+5}{15}$$\times$$\frac{5z}{81z^{2}-25}$=
$\frac{9z+5}{15}$$\times$$\frac{5z}{(9z)^{2}-5^{2}}$=
$\frac{9z+5}{15}$$\times$$\frac{5z}{(9z+5)(9z-5)}$=
$\frac{(9z+5)5z}{15(9z+5)(9z-5)}$=
$\frac{z}{3(9z-5)}$