## Algebra: A Combined Approach (4th Edition)

$\dfrac{x^{3}-4x}{x^{2}+3x+2}=\dfrac{x(x-2)}{x+1}$
$\dfrac{x^{3}-4x}{x^{2}+3x+2}$ Take out common factor $x$ from the numerator and factor the denominator: $\dfrac{x^{3}-4x}{x^{2}+3x+2}=\dfrac{x(x^{2}-4)}{(x+2)(x+1)}=...$ Factor $x^{2}-4$ in the numerator and simplify: $...=\dfrac{x(x-2)(x+2)}{(x+2)(x+1)}=\dfrac{x(x-2)}{x+1}$