Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Review: 9

Answer

$\dfrac{x^{3}-4x}{x^{2}+3x+2}=\dfrac{x(x-2)}{x+1}$

Work Step by Step

$\dfrac{x^{3}-4x}{x^{2}+3x+2}$ Take out common factor $x$ from the numerator and factor the denominator: $\dfrac{x^{3}-4x}{x^{2}+3x+2}=\dfrac{x(x^{2}-4)}{(x+2)(x+1)}=...$ Factor $x^{2}-4$ in the numerator and simplify: $...=\dfrac{x(x-2)(x+2)}{(x+2)(x+1)}=\dfrac{x(x-2)}{x+1}$
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