#### Answer

$\dfrac{-y^{3}}{8}\cdot\dfrac{9x^{2}}{y^{3}}=-\dfrac{9x^{2}}{8}$

#### Work Step by Step

$\dfrac{-y^{3}}{8}\cdot\dfrac{9x^{2}}{y^{3}}$
Evaluate the product and simplify by removing the factors that appear both in the numerator and the denominator of the resulting expression:
$\dfrac{-y^{3}}{8}\cdot\dfrac{9x^{2}}{y^{3}}=\dfrac{(-y^{3})(9x^{2})}{(8)(y^{3})}=-\dfrac{9x^{2}}{8}$