Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Review: 16

Answer

$\dfrac{-y^{3}}{8}\cdot\dfrac{9x^{2}}{y^{3}}=-\dfrac{9x^{2}}{8}$

Work Step by Step

$\dfrac{-y^{3}}{8}\cdot\dfrac{9x^{2}}{y^{3}}$ Evaluate the product and simplify by removing the factors that appear both in the numerator and the denominator of the resulting expression: $\dfrac{-y^{3}}{8}\cdot\dfrac{9x^{2}}{y^{3}}=\dfrac{(-y^{3})(9x^{2})}{(8)(y^{3})}=-\dfrac{9x^{2}}{8}$
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