Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Review: 23

Answer

$\dfrac{2x^{2}-9x+9}{8x-12}\div\dfrac{x^{2}-3x}{2x}=\dfrac{1}{2}$

Work Step by Step

$\dfrac{2x^{2}-9x+9}{8x-12}\div\dfrac{x^{2}-3x}{2x}$ Factor both rational expressions completely: $\dfrac{2x^{2}-9x+9}{8x-12}\div\dfrac{x^{2}-3x}{2x}=\dfrac{(2x-3)(x-3)}{4(2x-3)}\div\dfrac{x(x-3)}{2x}=...$ Evaluate the division and simplify by removing the factors that appear both in the numerator and the denominator of the resulting expression: $...=\dfrac{2x(2x-3)(x-3)}{4x(2x-3)(x-3)}=\dfrac{1}{2}$
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