## Algebra: A Combined Approach (4th Edition)

$\dfrac{2x^{2}-9x+9}{8x-12}\div\dfrac{x^{2}-3x}{2x}=\dfrac{1}{2}$
$\dfrac{2x^{2}-9x+9}{8x-12}\div\dfrac{x^{2}-3x}{2x}$ Factor both rational expressions completely: $\dfrac{2x^{2}-9x+9}{8x-12}\div\dfrac{x^{2}-3x}{2x}=\dfrac{(2x-3)(x-3)}{4(2x-3)}\div\dfrac{x(x-3)}{2x}=...$ Evaluate the division and simplify by removing the factors that appear both in the numerator and the denominator of the resulting expression: $...=\dfrac{2x(2x-3)(x-3)}{4x(2x-3)(x-3)}=\dfrac{1}{2}$