Answer
$\dfrac{x+5}{x-3}$
Work Step by Step
$\dfrac{x^2+5x-2x-10}{x^2-3x-2x+6} = \dfrac{x(x+5)-2(x+5)}{x(x-3)-2(x-3)} = \dfrac{(x+5)(x-2)}{(x-3)(x-2)} = \dfrac{x+5}{x-3}$
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