Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Review: 11

Answer

$\dfrac{x^{2}-x-6}{x^{2}-3x-10}=\dfrac{x-3}{x-5}$

Work Step by Step

$\dfrac{x^{2}-x-6}{x^{2}-3x-10}$ Factor the numerator and the denominator and then simplify:$\dfrac{x^{2}-x-6}{x^{2}-3x-10}=\dfrac{(x-3)(x+2)}{(x-5)(x+2)}=\dfrac{x-3}{x-5}$
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