## Algebra: A Combined Approach (4th Edition)

$6y^{2}-44y+14$ $2(3y-1)(y-7)$
Perimeter of a rectangle = 2*width + 2*length $2(3y^{2})+2(-22y+7)=6y^{2}-44y+14=perimeter$ $6y^{2}-44y+14=2(3y^{2}-22y+7)$ $3y^{2}-22y+7=(3y-1)(y-7)$ $2(3y-1)(y-7)$