Answer
Chapter 6 - Section 6.3 - Exercise Set: 100 (Answer)
$6x^2 + 7x + 1$ $\neq$ $(3x + 1)(2x + 1)$
The error is at $+7x$.
Work Step by Step
Chapter 6 - Section 6.3 - Exercise Set: 100 (Solution)
Explanation :
To check where is the error of $6x^2 + 7x + 1$ = $(3x + 1)(2x + 1)$
1) $3x\cdot 2x$ = $6x^2$ $\Rightarrow$ (Ok, correct)
2) $1\cdot1$ = $1$ $\Rightarrow$ (Ok, correct)
3) $3x\cdot 1$ + $1\cdot 2x$ = $5x$ $\Rightarrow$ (Not ok, incorrect, since it should be equal to $7x$)
In summary, $6x^2 + 7x + 1$ $\neq$ $(3x + 1)(2x + 1)$