Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.3 - Factoring Trinomials of the Form ax2+bx+c - Exercise Set: 95

Answer

Chapter 6 - Section 6.3 - Exercise Set: 95 (Answer) For $3x^2 + bx - 5$, all positive values of ‘b’ are 2 and 14.

Work Step by Step

Chapter 6 - Section 6.3 - Exercise Set: 95 (Solution) Explanation : $3x^2 + bx - 5$ = $(3x + p)(x + q)$ Since $p\cdot q$ = -5, p and q have to be of opposite signs For (p + 3q) = b and positive ‘b’ required, If p = 1, q = -5 then b = -14 (Incorrect result) If p = 5, q = -1 then b = 2 (Correct) If p = -1, q = 5 then b = 14 (Correct) If p = -5, q = 1 then b = -2 (Incorrect result) So, all positive values of ‘b’ are 2 and 14.
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