Algebra: A Combined Approach (4th Edition)

$\frac{(4x+1)^{2}}{4}$
$(4x^{2}+2x+\frac{1}{4})*4=16x^{2}+8x+1$ Make fractions whole $16x^{2}+8x+1=(4x+1)(4x+1)=(4x+1)^{2}$ $\frac{(4x+1)^{2}}{4}$ Divide by 4 again