Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Section 6.3 - Factoring Trinomials of the Form ax2+bx+c - Exercise Set: 94

Answer

$(a+3)^3(3x-25)(x-1)$

Work Step by Step

Given $3x^2(a+3)^3-28x(a+3)^3+25(a+3)^3 = (a+3)^3(3x^2-28x+25) = (a+3)^3(3x^2-3x-25x+25) = (a+3)^3[3x(x-1)-25(x-1)] = (a+3)^3(3x-25)(x-1)$
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