Chapter 5 - Section 5.2 - Negative Exponents and Scientific Notation - Exercise Set - Page 354: 70

$\dfrac{(a^{6}b^{-2})^{4}}{(4a^{-3}b^{-3})^{3}}=\dfrac{a^{33}b}{64}$

$\dfrac{(a^{6}b^{-2})^{4}}{(4a^{-3}b^{-3})^{3}}$ Evaluate the exponential expressions in the numerator and the denominator: $\dfrac{(a^{6}b^{-2})^{4}}{(4a^{-3}b^{-3})^{3}}=\dfrac{a^{24}b^{-8}}{64a^{-9}b^{-9}}=...$ Evaluate the division and simplify: $...=\dfrac{1}{64}a^{24-(-9)}b^{-8-(-9)}=\dfrac{1}{64}a^{33}b=\dfrac{a^{33}b}{64}$